大家好，我的数库里有一个表lac的字段是lac_hex,里面的数值是十六进制的，另一个表是lac_in，里面的字段lac是十进制的，
这两个表要进行关联，怎么实现lac_hex和lac的关联，也就是十六进制和十进制的转换
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你可以创建存储过程实现该转换
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http://topic.csdn.net/u/20070116/10/0c7d9ec1-acaa-4918-86cd-51516f7f517f.html
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CREATE FUNCTION dbo.f_hex_dec(@s varchar(16))
RETURNS bigint
AS
BEGIN
DECLARE @i int,@result bigint
SELECT @i=0,@result=0,@s=RTRIM(LTRIM(UPPER(REVERSE(@s))))
WHILE @i <LEN(@s)
BEGIN
IF SUBSTRING(@s,@i+1,1) not between '0 ' and '9 ' and SUBSTRING(@s,@i+1,1) not between 'A ' and 'F '
BEGIN
SELECT @result=0
参考一下
break
END
SELECT @[email protected]+(CHARINDEX(SUBSTRING(@s,@i+1,1), '0123456789ABCDEF ')-1)*POWER(16,@i),@[email protected]+1
END
RETURN @result
END
GO
--
select dbo.f_hex_dec( 'A ')
--res
10
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- SQL code
create Function [dbo].[IntToHex](@IntNum int)returns varchar(16)asbegin declare @Mods int,@res varchar(16) set @res='' while @IntNum <> 0 begin set @Mods [email protected] % 16 if @Mods > 9 set @res = Char(Ascii('A')[email protected])[email protected] else set @res = Cast(@Mods as varchar(4)) + @res set @IntNum = @IntNum/16 end return @resend
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- SQL code
create Function [dbo].[IntToHex](@IntNum int)returns varchar(16)asbegin declare @Mods int,@res varchar(16) set @res='' while @IntNum <> 0 begin set @Mods [email protected] % 16 if @Mods > 9 set @res = Char(Ascii('A')[email protected])[email protected] else set @res = Cast(@Mods as varchar(4)) + @res set @IntNum = @IntNum/16 end return @resendgodeclare @lac table (lac_hex varchar(2))insert into @lacselect 'A' union allselect 'AB' union allselect '2B'declare @lac_in table (lac int)insert into @lac_inselect 171 union allselect 10 union allselect 67select * from @lac a full join @lac_in b on dbo.[IntToHex](b.lac)=a.lac_hex/*lac_hex lac------- -----------AB 171A 10NULL 672B NULL(4 row(s) affected)*/