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servlet 得到 JavaWeb项目上某文件夹的路径

热度:364   发布时间:2013-03-01 18:33:02.0
servlet 得到 JavaWeb项目下某文件夹的路径

如果web项目下有upload这个文件夹

在web.xml设置

  <context-param>
    <param-name>upload folder</param-name>
    <param-value>upload</param-value>
  </context-param>



在servlet中通过下面语句可以得到upload文件夹的路径


public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
ServletContext context=getServletConfig().getServletContext();//获取上下文
String uploadpath=context.getInitParameter("upload folder");//获取参数

String path=context.getRealPath(uploadpath);//得到文件夹upload的实际路径(例如E:\Soft\tomcat\tomcat6\webapps\atest\upload)atest为项目名称



response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\">");
out.println("<HTML>");
out.println("  <HEAD><TITLE>A Servlet</TITLE></HEAD>");
out.println("  <BODY>");
out.print("uploadpath  : ");
out.print(path);
out.println(", using the GET method");
out.println("  </BODY>");
out.println("</HTML>");
out.flush();
out.close();
}

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