问题描述
我正在 Android 中使用 GoogleMap。
到目前为止，我已经获得了当前位置并在其上显示了标记。
我从当前位置获得了 LatLong 值。
我可以使用以下代码获取城市名称：
Geocoder gcd = new Geocoder(MainActivity.this, Locale.getDefault());
List<Address> addresses = null;
try {
addresses = gcd.getFromLocation( mLocation.getLatitude(), mLocation.getLongitude(), 1);
} catch (IOException e) {
e.printStackTrace();
}
if (addresses.size() > 0)
System.out.println(addresses.get(0).getLocality());
Toast.makeText(MainActivity.this,""+addresses.get(0).getLocality(),Toast.LENGTH_LONG).show();
}
但是，无法获得实际区域名称，即Bodakdev char rasta , Ahmedab??ad。
现在，我的问题是：如何从 LatLong 获取实际文本值（地名）？
1楼
您可以通过 Google 地图中的Geocoder对象获取此信息。
方法getFromLocation(double, double, int)完成这项工作。
Geocoder geocoder;
List<Address> addresses;
geocoder = new Geocoder(this, Locale.getDefault());
addresses = geocoder.getFromLocation(latitude, longitude, 1); // 1 represent max location result to returned, by documents it recommended 1 to 5
String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String country = addresses.get(0).getCountryName();
String postalCode = addresses.get(0).getPostalCode();
String knownName = addresses.get(0).getFeatureName();
2楼
用这个，
Geocoder geocoder = new Geocoder(this, Locale.getDefault());
List<Address> addresses = geocoder.getFromLocation(MyLat, MyLong, 1);
String cityName = addresses.get(0).getAddressLine(0);
String stateName = addresses.get(0).getAddressLine(1);
String countryName = addresses.get(0).getAddressLine(2);
String address = addresses.get(0).getAddressLine(0);
3楼
您还可以从地方的邮政编码或邮政编码中获取城市名称
private fun getLatLngByZipcode(zipcode: String): String {
var place = context.getString(R.string.location)
val geocoder = Geocoder(context, Locale.getDefault())
try {
val addresses = geocoder.getFromLocationName(zipcode, 5)
addresses?.forEach{
it?.locality?.apply {
place=this
}
}
}
catch (e: IOException) {
LogUtils.error(TAG,e.message)
}
return place
}