任意输入一个4位数,求他的数字之和,(如:5173,数字之和是:16

大数用字符串.

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#include"stdio.h"
#include"math.h"
main()
{int n,a,b,c,d,sum;
printf("please input n=:");
scanf("%d",&n);
a=n/10000;
b=n%1000/100;
c=n%1000%100/10;
d=n%1000%100%10;
sum=a+b+c+d;
printf("sum=%d\n",sum);}


这个程序就很简单了，而且很容易懂


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老夫也写一个
#include <stdio.h>

typedef char S8;
typedef int S32;

void main(void)
{
S32 num = 0, i = 0;
S8 array[16];

printf("Please input a number:");
scanf("%d", &num);
memset(array, 0, sizeof(array));
itoa(num, array, 10);

num = 0;
while(*(array+i))
{
num += *(array+i)-'0';
i++;
}
printf("result = %d", num);
getch();
}

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厉害啊

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看看
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