Java中一个关于判断循环的小问题

我想实现一个判断
如果判断a》b  或者 a<b则循环一直循环
再输入一个a和b比较  要是不行
再输入。。。
如果a=b  则跳出循环
代码如下 帮忙看看谢谢
package javazy;

import java.util.Random;
import java.util.Scanner;

public class P403nx1 {
public int hehe(){
    System.out.println("请输入一个整数");
    Scanner scanner = new Scanner(System.in);
    int Num = scanner.nextInt();
    return Num;
}
    public static void main(String[] args) {
        P403nx1 p = new P403nx1();
        Random rd = new Random();
        int a = p.hehe();
        int x = rd.nextInt(11)+0;
        System.out.println(x);
        while(true){
        if (a==x) {
            System.out.println("你太聪明了");
            break;
            
        }else if(a>x){
            System.out.println("大了");
            
        }else{
            System.out.println("xiaole");
            
        }
        return;
        }
        
    }
}
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import java.util.Random;
import java.util.Scanner;

public class P403nx1 {
public int hehe(){
    System.out.println("请输入一个整数");
    Scanner scanner = new Scanner(System.in);
    int Num = scanner.nextInt();
    return Num;
}
    public static void main(String[] args) {
        P403nx1 p = new P403nx1();
        Random rd = new Random();
        int a = p.hehe();
        int x = rd.nextInt(11)+0;
        System.out.println(x);
        while(true){
        if (a==x) {
            System.out.println("你太聪明了");
            break;
            
        }else if(a>x){
            System.out.println("大了");
            
        }else{
            System.out.println("xiaole");
            
        }
         a = p.hehe();
        }
        
    }
}
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楼上说的对，就是输入错误后没有给机会重新输入，判断的还是一开始输入的数，所以就无限的判断下去了。。。。
----------------解决方案--------------------------------------------------------