问题描述
搜索了很长时间后，我找不到任何对我有帮助的东西。 （我也是java新手）
我有一个这样的 XML 文件
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Personen>
<Person>
<birthday>2002-03-01</birthday>
<name>sad</name>
<comment>Test Comment</comment>
</Person>
<Person>
<birthday>1999-02-21</birthday>
<name>Test1</name>
<comment>Test Comment</comment>
</Person>
<Person>
<birthday>2005-02-21</birthday>
<name>Test2</name>
<comment>Test Comment</comment>
</Person>
</Personen>
我需要从文件中获取所有姓名和生日并将它们放入列表中：
$list->:
"sad","2002-03-01"
"Test1","1999-02-21"
"Test2","2005-02-21"
并且知道我完全不知道该怎么做。
1楼
找到这个并使用此代码后，我解决了我的问题
try {
File fXmlFile = new File("P:/example/exampleFile.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
//optional, but recommended
//read this - http://stackoverflow.com/questions/13786607/normalization-in-dom-parsing-with-java-how-does-it-work
doc.getDocumentElement().normalize();
System.out.println("Root element: " + doc.getDocumentElement().getNodeName());
NodeList nList = doc.getElementsByTagName("Person");
System.out.println("----------------------------");
for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = nList.item(temp);
System.out.println("\nCurrent Element: " + nNode.getNodeName());
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
System.out.println(eElement.getElementsByTagName("name").item(0).getTextContent());
System.out.println(eElement.getElementsByTagName("birthday").item(0).getTextContent());
}
}
} catch (Exception e) {
e.printStackTrace();
}