//1.如何定义字典//1> 定义不可变字典：使用let修饰//编译器会根据[]中每一个元素（数组），还是健值队（字典）//写法一let dict3 : Dictionary<String, Any> = ["sww": 123,"frg":"911"]//写法二let dict2 = ["sww": 123,"frg":"911"] as [String : Any]//写法三，常用写法let dict1 : [String: Any] = ["sww": 123,"frg":"911"]print(dict1,dict2,dict3)//2.如何定义可变字典//1> 定义可变字典：使用var修饰//写法一var dict4 = Dictionary<String,Any>()//写法二var dicm5 = [String : Any]()print(dict4,dicm5)//2> 对可变字典添加元素dict4["name"] = "why" //没有oc中的setonjectledict4["age"] = 20dict4["height"] = 1.88//3》删除元素dict4.removeValue(forKey:"name")//4> 修改元素dict4["name"] = "lmj"dict4.updateValue("lmj", forKey: "name")//5>查找元素//dicm["age"]//3.遍历//遍历所有的valuesfor value in dict4.values{print(value)}//遍历所有的keyfor key in dict4.keys{print(key)}//4.字典合并
var dict7 :[String:Any] = ["name":"why", "age":10]
let dict8 :[String:Any] = ["height":1.88, "phonenumber":"110"]//let result = dict1 + dict2
for (key, value) in dict8 {dict7[key] = value
}print(dict7)