ctypes 函数指针作为参数

#include<stdio.h>
void show() {
          printf("%s\n",__FUNCTION__);
}void cool(void(**s)()){
          *s = &show;
}
~

• 赋值的是show

• gcc -fPIC --shared test.c -o test.so

import ctypes
VOID_T = ctypes.CFUNCTYPE(None)
t = VOID_T()handle=ctypes.CDLL("./test.so")
handle.cool.argtypes=[ctypes.POINTER(VOID_T)]
handle.cool(ctypes.pointer(t))
t()

• 输出函数名show.