当前位置: 代码迷 >> 综合 >> 题目1439:Least Common Multiple 九度OJ
  详细解决方案

题目1439:Least Common Multiple 九度OJ

热度:48   发布时间:2023-09-24 06:41:48.0

题目1439:Least Common Multiple

时间限制:1 秒

内存限制:128 兆

特殊判题:

提交:5944

解决:1771

题目描述:

The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.

输入:

Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.

输出:

For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.

样例输入:
2
3 5 7 15
6 4 10296 936 1287 792 1
样例输出:
105
10296

#include <cstdio>int gcd(long long a,long long b){if(b==0)return a;else gcd(b,a%b);
}int main(){int n;while(scanf("%d",&n)!=EOF){while(n--){int m;scanf("%d",&m);long long a,b;scanf("%lld",&a);m--;while(m--){scanf("%lld",&b);a=a*b/gcd(a,b);}printf("%lld\n",a);}}return 0;
}


注意题中所说的32-bit integer, 是unsigned

  相关解决方案