?刚开始学习JQuery，也可以说是笔记吧，Jquery简化大量JS工作。今天我们来做一个类似登录功能；
我们来看看Client的代码
<script type="text/javascript" src="jquery/jquery.js"></script>
</head>
<script type="text/javascript">
function check(){
var queryString={name:encodeURI($("#name").val())};
// $.get("servlet/check",queryString,function(data){
// $("#ok").html(decodeURI(data));
// });
//
$.post("servlet/check",queryString,function(data){
$("#ok").html(decodeURI(data));
});
}
</script>
<body>
name: <input type="text" id="name" onblur="check();"><div id="ok"></div>
<input type="button" value="go" onclick="starta();">
?Server代码
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
String name=request.getParameter("name").toString();
//response.setContentType("text/xml");把这个注释去掉就有危险
PrintWriter out = response.getWriter();
if(name.equalsIgnoreCase("nic")){
out.println(" <p>用户已存在");
out.println("</p>");
}else{
out.println(" <p>"+request.getParameter("name"));
out.println("</p>");
}
out.flush();
out.close();
}
/**
* The doPost method of the servlet. <br>
*
* This method is called when a form has its tag value method equals to post.
*
* @param request the request send by the client to the server
* @param response the response send by the server to the client
* @throws ServletException if an error occurred
* @throws IOException if an error occurred
*/
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
doGet(request,response);
}
?web.xml
<servlet>
<servlet-name>check</servlet-name>
<servlet-class>check</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>check</servlet-name>
<url-pattern>/servlet/check</url-pattern>
</servlet-mapping>
?
做一篇试试吧！！