最简单的String List的实现
?
?
?
实现步骤：
1.在xml布局文件中添加ListView控件节点并且设置好相关属性
2.在activity里findViewById 找到ListView控件对象
3.创建ListView的适配器adapter (这里采用ArrayAdapter<String> adapter)
4.给ListView绑定adapter
5.通过adapter往ListView里添加item
?
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools" android:layout_width="match_parent" android:layout_height="match_parent" android:paddingBottom="@dimen/activity_vertical_margin" android:paddingLeft="@dimen/activity_horizontal_margin" android:paddingRight="@dimen/activity_horizontal_margin" android:paddingTop="@dimen/activity_vertical_margin" tools:context="cn.jinyejun.ui_listview.MainActivity" > <ListView android:id="@+id/lv_main" android:layout_width="fill_parent" android:layout_height="fill_parent" > </ListView></RelativeLayout>
package cn.jinyejun.ui_listview;import android.os.Bundle;import android.support.v7.app.ActionBarActivity;import android.widget.ArrayAdapter;import android.widget.ListView;public class MainActivity extends ActionBarActivity { private ListView lv; //ListView组件 private ArrayAdapter<String> adapter; //ListView组件的适配器 @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); //创建ListView的适配器adapter用来适配ListView里的布局风格和布局内容 adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1); //通过id索引到ListView的组件 lv = (ListView) findViewById(R.id.lv_main); //给ListView添加适配器 lv.setAdapter(adapter); //通过adapter往ListView里面添加内容 adapter.add("item1"); adapter.add("item2"); adapter.add("item3"); adapter.add("item4"); adapter.add("item5"); adapter.add("item6"); }}?
?
?
?