当前位置: 代码迷 >> JavaScript >> JS习题-拖拽Drag and Drop
  详细解决方案

JS习题-拖拽Drag and Drop

热度:689   发布时间:2012-11-22 00:16:41.0
JS练习-拖拽Drag and Drop

最近看书,练习下,写了个简单的拖拽

?

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>简单拖拽</title>
<style type="text/css">
html,body{overflow:hidden;}
body,div,h2,p{margin:0;padding:0;}
body{color:#fff;background:#000;font:12px/2 Arial;}
p{padding:0 10px;margin-top:10px;}
span{color:#ff0;padding-left:5px;}
#wrapper{position:absolute;width:300px;height:150px;background:#333;border:2px solid #ccc; cursor:move;}
</style>

</head>

<body>
<div id="wrapper">
	<p>This is a box.</p>
</div>
</body>
</html>
?

?

?

<script type="text/javascript">
window.onload = function(){
	var oDiv = document.getElementById("wrapper");
	var posX,posY;
	var listener = false;
	oDiv.onmousedown = function(e){
		e = e || window.event;
		listener = true;
		posX = e.clientX - parseInt(oDiv.offsetLeft);
		posY = e.clientY - parseInt(oDiv.offsetTop);
		return false;
		};
	document.onmousemove = function(e){
		e = e || window.event;
		if (listener == true){
			oDiv.style.left = e.clientX - posX + "px";
			oDiv.style.top = e.clientY - posY + "px";
		}
		return false;
		};
	document.onmouseup=function(){
		listener=false;
		};
	}
</script>

?大牛们轻拍,本人菜鸟

  相关解决方案