字符串：{user:link islocal='1'} /2013/userup/100/131a2Z34-800.doc {/user:link}
如何提取出/2013/userup/100/131a2Z34-800.doc
------解决方案--------------------
$str = "{user:link islocal='1'} /2013/userup/100/131a2Z34-800.doc {/user:link}";
$preg = "#\{.*\}(.*)\{.*\}#iuUs";
preg_match_all($preg, $str, $matches);
print_r($matches[1]);
------解决方案--------------------
正则 #}\s*(\S+)\s*{#
或者用split()依据空格或花括号切分也能得到