按要求数据配对？解决方案

/*有一张表（大约200万条记录）。为方便测试，剔除无关信息，随机生成10000行记录，保留3列，记为：test（usrid，value，u_type）,其中usrid唯一，value在1000范围以内，u_type为‘Yes'或‘No’。--要求：选择表中value值相同但u_type不同的记录，将其usrid成对找出来。如果有1对多，多对1，--      多对多情形，则任选其一，使其成为1对1.--例如：如果原始表为：usrid    value    u_type1          1        Yes 2          34       No4          86       No5          34       No6          7        Yes8          1        Yes9          1        No3          10       Yes89         10       Yes78         7        No14         2        No66         2        Yes102        2        No708        8        Yes84         8        No99         8        Yes182        8        No最终表为（2行）：Usrid_Yes    Usrid_No1              96              7866             1499             84这里像value为1的记录，u_type有2个Yes，1个No。属于多对1，那么任意挑一个Yes和No的记录，找出其usrid（1和9）。value为2,8的记录属于1对多，多对多，做类似处理。--说明一下，使用类似下面的cross join的方法，大数据量时，不太可行。select     t1.usr ,    t1.u_type,    t2.usr ,    t2.u_typefrom test2 t1,test2 t2where t1.value=t2.value and t1.u_type!=t2.u_type and t1.usr!=t2.usrorder by t1.usr,t2.usr。。。*/--随机生成数据if OBJECT_ID('test2') is not nulldrop table test2gocreate table test2(usrid int,value int,u_type varchar(5))declare @i intset @i=1while @i<=10000begin    insert into test2 values(@i,ABS(CHECKSUM(newid())%1000),ABS(CHECKSUM(newid()))%2)    set @[email protected]+1endupdate test2set u_type=case u_type when 1 then 'Yes'               when 0 then 'No' end from test2 --select count(1) from test2 

-->tryselect a.usrid,a.value from(select row_number() over(partition by value order by value) rn,* from test2)ainner join (select value from test2 group by value having count(distinct u_type)>1) bon a.value=b.valuewhere a.rn=1
------解决方案--------------------
with tt as (
	select value  
	from test  
	group by value
	having COUNT(distinct u_type)>1
)
select  
	(select top 1 usrid from test t where t.value=tt.value and t.u_type='Yes') Usrid_Yes ,
	(select top 1 usrid from test t where t.value=tt.value and t.u_type='No') Usrid_No  
from tt

------解决方案--------------------
SQL code
 with t as ( select value,u_type,usrid, ROW_NUMBER() over (partition by value,u_type order by usrid) as rn from test2   ),tYes as( select * From t where u_type='Yes' and rn=1 ) ,tNo as ( select * From t where u_type='No' and rn=1 ) select a.usrid as Usrid_Yes,b.usrid as Usrid_No from tYes a join tNo b  on a.value=b.value    order by a.usrid